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kinamatics (Question)

manojkalkhuria said – Sun, 20 Sep 2009 02:27:45 -0000 ( Link )

Two particles are initially located at ‘P’ & ‘Q’,separated by a distance ‘d’.They start moving in such a way that velocity ‘u’ of ‘Q’ is always along the horizontal and the velocity ‘v’ of ‘P’ is always directed towards ‘Q’.Determine when the two particles meat?Given that ‘u’ is initially perpendicular to ‘v’.

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6 Answers

  1. angadyuvraj said – Wed, 23 Sep 2009 08:29:58 -0000 ( Link )

    They will meet at tiime t=d/sqrt(vv-uu)

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  2. pooja goud said – Thu, 24 Sep 2009 00:27:13 -0000 ( Link )

    they will meet at t=d

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  3. sumils said – Fri, 25 Sep 2009 08:57:38 -0000 ( Link )

    they will meet at t=d/(v-u)

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  4. geetikadadheech12 said – Sat, 26 Sep 2009 18:49:12 -0000 ( Link )

    they will meet at a time vd/v2-u2

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  5. jeetender8 said – Tue, 29 Sep 2009 12:44:31 -0000 ( Link )

    they will meet at time t=d/v-u

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  6. raghav sood said – Wed, 14 Oct 2009 02:58:25 -0000 ( Link )

    t=d/v+u or t=d/|v-u|

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